[winswitch] (no subject)

[Konstantin Pelepelin]

Hello!

A new user is here with newbie questions.

I use Windows 10 Xpra GTK3 client version 3.0.5-r24942 64-bit, unpacked
from zip.

If I use Xpra-Launcher.exe, I get a fancy tray icon with all the menus, but
I can't issue "start" command if xpra server is not running yet. That's a
pity.
If I use Xpra.exe or Xpra_cmd.exe, I can start the remote server, but I
don't get the tray icon. There may be something in these lines:

> Traceback (most recent call last):
>   File "E:\Xpra\tags\v3.0.x\src/xpra/client/mixins/tray.py", line 49, in
> setup_xpra_tray
>   File "E:\Xpra\tags\v3.0.x\src/xpra/client/mixins/tray.py", line 111, in
> create_xpra_tray
>   File "E:\Xpra\tags\v3.0.x\src/xpra/client/mixins/tray.py", line 138, in
> get_tray_title
> TypeError: sequence item 0: expected str instance, tuple found


So, if I use "xpra start", I can't detach and exit it other than killing
the process.

Additionally, if I run "xpra start" when the server is already running,
instead of attaching to the already running server it hangs for some time,
and then bails out with

> 2020-02-06 14:57:21,858 Error: failed to receive anything, not an xpra
> server?
> 2020-02-06 14:57:21,859   could also be the wrong protocol, username,
> password or port
> 2020-02-06 14:57:21,860   or the session was not found
> 2020-02-06 14:57:21,861 Connection lost


I understand the last one can be intentional, but if I don't remember if
the server was already started, what would be a solution to quickly start
and attach to the server? I'd use something like `xpra start
ssh:user at ubuntu:100
--start-child=pcmanfm` but with the 2 problems above it takes many manual
actions: `xpra start ssh:user at ubuntu:100`, wait for start and ctrl-c to
detach or wait for apparent failure because it's already started, then open
launcher and attach from it.

Do I miss something?

xpra server is 3.0.5-r24939 on Ubuntu 18.04

Thanks for your fantastic project!

Konstantin